The winning Delaware Play 4 numbers for September 7, 2003 were: night 6-2-6-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 7, 2003 | Night | 6-2-6-1 | 15 | 6 |
| Sep 6, 2003 | Night | 3-1-7-6 | 17 | 8 |
| Sep 6, 2003 | Day | 3-0-0-0 | 3 | 3 |
| Sep 5, 2003 | Night | 0-7-2-1 | 10 | 1 |
| Sep 5, 2003 | Day | 7-8-2-1 | 18 | 9 |
| Sep 4, 2003 | Night | 3-0-3-6 | 12 | 3 |
| Sep 4, 2003 | Day | 4-7-3-2 | 16 | 7 |
| Sep 3, 2003 | Night | 9-0-4-3 | 16 | 7 |
| Sep 3, 2003 | Day | 7-4-8-2 | 21 | 3 |
| Sep 2, 2003 | Night | 1-7-9-7 | 24 | 6 |
| Sep 2, 2003 | Day | 4-6-4-2 | 16 | 7 |
| Sep 1, 2003 | Night | 9-8-4-7 | 28 | 1 |
| Sep 1, 2003 | Day | 5-5-1-3 | 14 | 5 |