The winning Delaware Play 4 numbers for August 31, 2003 were: night 6-6-2-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 31, 2003 | Night | 6-6-2-0 | 14 | 5 |
| Aug 30, 2003 | Night | 2-9-1-8 | 20 | 2 |
| Aug 30, 2003 | Day | 4-7-8-0 | 19 | 1 |
| Aug 29, 2003 | Night | 8-3-3-2 | 16 | 7 |
| Aug 29, 2003 | Day | 7-6-7-9 | 29 | 2 |
| Aug 28, 2003 | Night | 7-5-7-8 | 27 | 9 |
| Aug 28, 2003 | Day | 3-3-3-9 | 18 | 9 |
| Aug 27, 2003 | Night | 9-7-5-5 | 26 | 8 |
| Aug 27, 2003 | Day | 4-5-0-7 | 16 | 7 |
| Aug 26, 2003 | Night | 6-0-5-4 | 15 | 6 |
| Aug 26, 2003 | Day | 1-3-8-4 | 16 | 7 |
| Aug 25, 2003 | Night | 4-4-7-2 | 17 | 8 |
| Aug 25, 2003 | Day | 0-9-9-2 | 20 | 2 |