The winning Delaware Play 4 numbers for August 10, 2003 were: night 5-4-9-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 10, 2003 | Night | 5-4-9-5 | 23 | 5 |
| Aug 9, 2003 | Night | 9-9-5-9 | 32 | 5 |
| Aug 9, 2003 | Day | 1-9-4-0 | 14 | 5 |
| Aug 8, 2003 | Night | 3-3-2-2 | 10 | 1 |
| Aug 8, 2003 | Day | 6-8-4-4 | 22 | 4 |
| Aug 7, 2003 | Night | 8-3-1-9 | 21 | 3 |
| Aug 7, 2003 | Day | 7-4-5-1 | 17 | 8 |
| Aug 6, 2003 | Night | 7-2-7-2 | 18 | 9 |
| Aug 6, 2003 | Day | 1-9-5-8 | 23 | 5 |
| Aug 5, 2003 | Night | 6-4-2-1 | 13 | 4 |
| Aug 5, 2003 | Day | 3-5-5-4 | 17 | 8 |
| Aug 4, 2003 | Night | 0-8-9-5 | 22 | 4 |
| Aug 4, 2003 | Day | 1-0-6-9 | 16 | 7 |