The winning Delaware Play 4 numbers for July 13, 2003 were: night 5-7-9-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 13, 2003 | Night | 5-7-9-5 | 26 | 8 |
| Jul 12, 2003 | Night | 8-4-0-3 | 15 | 6 |
| Jul 12, 2003 | Day | 1-8-7-2 | 18 | 9 |
| Jul 11, 2003 | Night | 4-6-0-2 | 12 | 3 |
| Jul 11, 2003 | Day | 2-7-1-3 | 13 | 4 |
| Jul 10, 2003 | Night | 0-1-7-6 | 14 | 5 |
| Jul 10, 2003 | Day | 4-3-7-0 | 14 | 5 |
| Jul 9, 2003 | Night | 6-3-5-2 | 16 | 7 |
| Jul 9, 2003 | Day | 9-2-3-7 | 21 | 3 |
| Jul 8, 2003 | Night | 8-4-0-5 | 17 | 8 |
| Jul 8, 2003 | Day | 7-1-6-0 | 14 | 5 |
| Jul 7, 2003 | Night | 5-6-2-6 | 19 | 1 |
| Jul 7, 2003 | Day | 4-8-2-9 | 23 | 5 |