The winning Delaware Play 4 numbers for January 5, 2003 were: night 9-0-4-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 5, 2003 | Night | 9-0-4-6 | 19 | 1 |
| Jan 4, 2003 | Night | 4-0-7-7 | 18 | 9 |
| Jan 4, 2003 | Day | 4-9-7-9 | 29 | 2 |
| Jan 3, 2003 | Night | 6-7-5-1 | 19 | 1 |
| Jan 3, 2003 | Day | 8-6-4-2 | 20 | 2 |
| Jan 2, 2003 | Night | 5-2-2-1 | 10 | 1 |
| Jan 2, 2003 | Day | 6-4-3-5 | 18 | 9 |
| Jan 1, 2003 | Night | 0-7-9-9 | 25 | 7 |
| Jan 1, 2003 | Day | 8-6-1-4 | 19 | 1 |
| Dec 31, 2002 | Night | 5-9-1-6 | 21 | 3 |
| Dec 31, 2002 | Day | 9-5-9-9 | 32 | 5 |
| Dec 30, 2002 | Night | 6-8-3-4 | 21 | 3 |
| Dec 30, 2002 | Day | 6-4-0-1 | 11 | 2 |