The winning Delaware Play 4 numbers for December 26, 1999 were: night 3-0-0-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 26, 1999 | Night | 3-0-0-6 | 9 | 9 |
| Dec 24, 1999 | Night | 3-4-7-1 | 15 | 6 |
| Dec 24, 1999 | Day | 0-0-0-9 | 9 | 9 |
| Dec 23, 1999 | Night | 4-8-3-2 | 17 | 8 |
| Dec 23, 1999 | Day | 9-5-4-1 | 19 | 1 |
| Dec 22, 1999 | Night | 7-9-6-8 | 30 | 3 |
| Dec 22, 1999 | Day | 7-0-7-0 | 14 | 5 |
| Dec 21, 1999 | Night | 5-3-0-6 | 14 | 5 |
| Dec 21, 1999 | Day | 1-2-9-9 | 21 | 3 |
| Dec 20, 1999 | Night | 3-8-2-0 | 13 | 4 |
| Dec 20, 1999 | Day | 1-8-3-8 | 20 | 2 |