The winning Delaware Play 4 numbers for December 10, 1999 were: day 5-0-2-6; night 2-0-9-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 10, 1999 | Night | 2-0-9-3 | 14 | 5 |
| Dec 10, 1999 | Day | 5-0-2-6 | 13 | 4 |
| Dec 9, 1999 | Night | 4-0-4-9 | 17 | 8 |
| Dec 9, 1999 | Day | 9-5-7-0 | 21 | 3 |
| Dec 8, 1999 | Night | 3-1-0-6 | 10 | 1 |
| Dec 8, 1999 | Day | 4-3-5-7 | 19 | 1 |
| Dec 7, 1999 | Night | 9-1-8-8 | 26 | 8 |
| Dec 7, 1999 | Day | 8-2-3-9 | 22 | 4 |
| Dec 6, 1999 | Night | 6-7-1-7 | 21 | 3 |
| Dec 6, 1999 | Day | 5-5-1-5 | 16 | 7 |
| Dec 5, 1999 | Night | 9-0-3-4 | 16 | 7 |
| Dec 4, 1999 | Night | 6-8-4-2 | 20 | 2 |
| Dec 4, 1999 | Day | 8-4-2-9 | 23 | 5 |