The winning Delaware Play 4 numbers for December 1, 1999 were: day 0-3-8-3; night 7-6-3-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 1, 1999 | Night | 7-6-3-4 | 20 | 2 |
| Dec 1, 1999 | Day | 0-3-8-3 | 14 | 5 |
| Nov 30, 1999 | Night | 3-4-0-9 | 16 | 7 |
| Nov 30, 1999 | Day | 7-4-1-0 | 12 | 3 |
| Nov 29, 1999 | Night | 8-1-3-1 | 13 | 4 |
| Nov 29, 1999 | Day | 4-3-1-2 | 10 | 1 |
| Nov 28, 1999 | Night | 0-6-9-1 | 16 | 7 |
| Nov 27, 1999 | Night | 1-5-1-2 | 9 | 9 |
| Nov 27, 1999 | Day | 8-2-6-1 | 17 | 8 |
| Nov 26, 1999 | Night | 3-7-0-7 | 17 | 8 |
| Nov 26, 1999 | Day | 8-6-2-1 | 17 | 8 |
| Nov 25, 1999 | Night | 8-6-1-0 | 15 | 6 |
| Nov 25, 1999 | Day | 0-7-7-1 | 15 | 6 |