The winning Delaware Play 4 numbers for November 16, 1999 were: day 8-9-2-8; night 3-8-8-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 16, 1999 | Night | 3-8-8-0 | 19 | 1 |
| Nov 16, 1999 | Day | 8-9-2-8 | 27 | 9 |
| Nov 15, 1999 | Night | 8-3-7-6 | 24 | 6 |
| Nov 15, 1999 | Day | 6-8-0-8 | 22 | 4 |
| Nov 14, 1999 | Night | 0-3-8-5 | 16 | 7 |
| Nov 13, 1999 | Night | 0-2-2-5 | 9 | 9 |
| Nov 13, 1999 | Day | 4-4-0-1 | 9 | 9 |
| Nov 12, 1999 | Night | 4-9-4-9 | 26 | 8 |
| Nov 12, 1999 | Day | 7-6-4-8 | 25 | 7 |
| Nov 11, 1999 | Night | 5-2-5-9 | 21 | 3 |
| Nov 11, 1999 | Day | 2-7-1-8 | 18 | 9 |
| Nov 10, 1999 | Night | 8-3-3-4 | 18 | 9 |
| Nov 10, 1999 | Day | 6-7-0-1 | 14 | 5 |