The winning Delaware Play 4 numbers for November 2, 1999 were: day 8-7-3-3; night 9-8-8-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 2, 1999 | Night | 9-8-8-6 | 31 | 4 |
| Nov 2, 1999 | Day | 8-7-3-3 | 21 | 3 |
| Nov 1, 1999 | Night | 4-3-5-6 | 18 | 9 |
| Nov 1, 1999 | Day | 7-4-7-2 | 20 | 2 |
| Oct 31, 1999 | Night | 0-3-9-1 | 13 | 4 |
| Oct 30, 1999 | Night | 4-8-7-9 | 28 | 1 |
| Oct 30, 1999 | Day | 8-3-5-3 | 19 | 1 |
| Oct 29, 1999 | Night | 9-7-9-5 | 30 | 3 |
| Oct 29, 1999 | Day | 0-2-7-4 | 13 | 4 |
| Oct 28, 1999 | Night | 6-1-3-0 | 10 | 1 |
| Oct 28, 1999 | Day | 1-7-9-5 | 22 | 4 |
| Oct 27, 1999 | Night | 4-0-7-9 | 20 | 2 |
| Oct 27, 1999 | Day | 7-7-6-6 | 26 | 8 |