The winning Delaware Play 4 numbers for October 16, 1999 were: day 9-6-7-4; night 1-0-4-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 16, 1999 | Night | 1-0-4-5 | 10 | 1 |
| Oct 16, 1999 | Day | 9-6-7-4 | 26 | 8 |
| Oct 15, 1999 | Night | 8-1-7-0 | 16 | 7 |
| Oct 15, 1999 | Day | 6-3-9-9 | 27 | 9 |
| Oct 14, 1999 | Night | 6-8-4-3 | 21 | 3 |
| Oct 14, 1999 | Day | 2-4-9-7 | 22 | 4 |
| Oct 13, 1999 | Night | 3-3-9-5 | 20 | 2 |
| Oct 13, 1999 | Day | 3-2-2-0 | 7 | 7 |
| Oct 12, 1999 | Night | 9-4-4-2 | 19 | 1 |
| Oct 12, 1999 | Day | 8-5-7-6 | 26 | 8 |
| Oct 11, 1999 | Night | 1-5-5-5 | 16 | 7 |
| Oct 11, 1999 | Day | 0-7-9-9 | 25 | 7 |
| Oct 10, 1999 | Night | 3-8-6-5 | 22 | 4 |