The winning Delaware Play 4 numbers for October 10, 1999 were: night 3-8-6-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 10, 1999 | Night | 3-8-6-5 | 22 | 4 |
| Oct 9, 1999 | Night | 4-6-6-3 | 19 | 1 |
| Oct 9, 1999 | Day | 1-6-5-7 | 19 | 1 |
| Oct 8, 1999 | Night | 7-9-6-3 | 25 | 7 |
| Oct 8, 1999 | Day | 3-5-9-4 | 21 | 3 |
| Oct 7, 1999 | Night | 7-6-1-8 | 22 | 4 |
| Oct 7, 1999 | Day | 4-8-9-8 | 29 | 2 |
| Oct 6, 1999 | Night | 7-1-6-2 | 16 | 7 |
| Oct 6, 1999 | Day | 1-2-1-9 | 13 | 4 |
| Oct 5, 1999 | Night | 1-8-9-1 | 19 | 1 |
| Oct 5, 1999 | Day | 8-4-1-0 | 13 | 4 |
| Oct 4, 1999 | Night | 9-9-3-5 | 26 | 8 |
| Oct 4, 1999 | Day | 1-3-3-4 | 11 | 2 |