The winning Delaware Play 4 numbers for October 7, 1999 were: day 4-8-9-8; night 7-6-1-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 7, 1999 | Night | 7-6-1-8 | 22 | 4 |
| Oct 7, 1999 | Day | 4-8-9-8 | 29 | 2 |
| Oct 6, 1999 | Night | 7-1-6-2 | 16 | 7 |
| Oct 6, 1999 | Day | 1-2-1-9 | 13 | 4 |
| Oct 5, 1999 | Night | 1-8-9-1 | 19 | 1 |
| Oct 5, 1999 | Day | 8-4-1-0 | 13 | 4 |
| Oct 4, 1999 | Night | 9-9-3-5 | 26 | 8 |
| Oct 4, 1999 | Day | 1-3-3-4 | 11 | 2 |
| Oct 3, 1999 | Night | 5-0-9-1 | 15 | 6 |
| Oct 2, 1999 | Night | 1-0-8-1 | 10 | 1 |
| Oct 2, 1999 | Day | 0-8-3-5 | 16 | 7 |
| Oct 1, 1999 | Night | 4-3-5-2 | 14 | 5 |
| Oct 1, 1999 | Day | 9-8-7-3 | 27 | 9 |