The winning Delaware Play 4 numbers for September 24, 1999 were: day 0-1-8-3; night 4-1-2-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 24, 1999 | Night | 4-1-2-1 | 8 | 8 |
| Sep 24, 1999 | Day | 0-1-8-3 | 12 | 3 |
| Sep 23, 1999 | Night | 8-9-2-2 | 21 | 3 |
| Sep 23, 1999 | Day | 7-3-2-7 | 19 | 1 |
| Sep 22, 1999 | Night | 9-1-0-4 | 14 | 5 |
| Sep 22, 1999 | Day | 8-6-2-8 | 24 | 6 |
| Sep 21, 1999 | Night | 7-5-4-7 | 23 | 5 |
| Sep 21, 1999 | Day | 7-3-6-2 | 18 | 9 |
| Sep 20, 1999 | Night | 9-2-9-2 | 22 | 4 |
| Sep 20, 1999 | Day | 5-2-5-8 | 20 | 2 |
| Sep 19, 1999 | Night | 9-8-5-4 | 26 | 8 |
| Sep 18, 1999 | Night | 5-9-8-5 | 27 | 9 |
| Sep 18, 1999 | Day | 8-1-0-0 | 9 | 9 |