The winning Delaware Play 4 numbers for September 7, 1999 were: day 2-6-8-3; night 6-1-8-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 7, 1999 | Night | 6-1-8-8 | 23 | 5 |
| Sep 7, 1999 | Day | 2-6-8-3 | 19 | 1 |
| Sep 6, 1999 | Night | 3-8-0-3 | 14 | 5 |
| Sep 6, 1999 | Day | 9-6-6-5 | 26 | 8 |
| Sep 5, 1999 | Night | 0-4-6-4 | 14 | 5 |
| Sep 4, 1999 | Night | 3-2-6-8 | 19 | 1 |
| Sep 4, 1999 | Day | 6-7-1-1 | 15 | 6 |
| Sep 3, 1999 | Night | 8-3-5-0 | 16 | 7 |
| Sep 3, 1999 | Day | 9-3-4-5 | 21 | 3 |
| Sep 2, 1999 | Night | 4-0-0-4 | 8 | 8 |
| Sep 2, 1999 | Day | 2-6-0-9 | 17 | 8 |
| Sep 1, 1999 | Night | 2-7-5-8 | 22 | 4 |
| Sep 1, 1999 | Day | 2-5-3-8 | 18 | 9 |