The winning Delaware Play 4 numbers for August 27, 1999 were: day 6-5-3-8; night 4-3-3-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 27, 1999 | Night | 4-3-3-6 | 16 | 7 |
| Aug 27, 1999 | Day | 6-5-3-8 | 22 | 4 |
| Aug 26, 1999 | Night | 8-6-5-1 | 20 | 2 |
| Aug 26, 1999 | Day | 9-1-8-1 | 19 | 1 |
| Aug 25, 1999 | Night | 9-3-0-3 | 15 | 6 |
| Aug 25, 1999 | Day | 4-7-3-9 | 23 | 5 |
| Aug 24, 1999 | Night | 7-5-2-5 | 19 | 1 |
| Aug 24, 1999 | Day | 4-0-5-4 | 13 | 4 |
| Aug 23, 1999 | Night | 7-6-8-2 | 23 | 5 |
| Aug 23, 1999 | Day | 0-3-4-2 | 9 | 9 |
| Aug 22, 1999 | Night | 6-0-6-3 | 15 | 6 |
| Aug 21, 1999 | Night | 3-3-0-8 | 14 | 5 |
| Aug 21, 1999 | Day | 6-6-0-8 | 20 | 2 |