The winning Delaware Play 4 numbers for August 18, 1999 were: day 4-2-9-4; night 7-1-3-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 18, 1999 | Night | 7-1-3-6 | 17 | 8 |
| Aug 18, 1999 | Day | 4-2-9-4 | 19 | 1 |
| Aug 17, 1999 | Night | 0-3-4-7 | 14 | 5 |
| Aug 17, 1999 | Day | 7-7-0-4 | 18 | 9 |
| Aug 16, 1999 | Night | 1-1-8-9 | 19 | 1 |
| Aug 16, 1999 | Day | 7-8-1-2 | 18 | 9 |
| Aug 15, 1999 | Night | 9-6-5-5 | 25 | 7 |
| Aug 14, 1999 | Night | 8-4-0-2 | 14 | 5 |
| Aug 14, 1999 | Day | 3-4-8-0 | 15 | 6 |
| Aug 13, 1999 | Night | 3-3-5-8 | 19 | 1 |
| Aug 13, 1999 | Day | 2-2-8-4 | 16 | 7 |
| Aug 12, 1999 | Night | 6-1-3-6 | 16 | 7 |
| Aug 12, 1999 | Day | 3-1-1-7 | 12 | 3 |