The winning Delaware Play 4 numbers for August 10, 1999 were: day 5-2-4-4; night 3-4-4-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 10, 1999 | Night | 3-4-4-6 | 17 | 8 |
| Aug 10, 1999 | Day | 5-2-4-4 | 15 | 6 |
| Aug 9, 1999 | Night | 4-7-3-7 | 21 | 3 |
| Aug 9, 1999 | Day | 4-0-0-7 | 11 | 2 |
| Aug 8, 1999 | Night | 9-3-3-6 | 21 | 3 |
| Aug 7, 1999 | Night | 7-3-1-7 | 18 | 9 |
| Aug 7, 1999 | Day | 4-6-2-3 | 15 | 6 |
| Aug 6, 1999 | Night | 9-0-7-5 | 21 | 3 |
| Aug 6, 1999 | Day | 9-3-1-7 | 20 | 2 |
| Aug 5, 1999 | Night | 0-5-4-0 | 9 | 9 |
| Aug 5, 1999 | Day | 8-7-1-0 | 16 | 7 |
| Aug 4, 1999 | Night | 0-0-7-3 | 10 | 1 |
| Aug 4, 1999 | Day | 0-8-1-3 | 12 | 3 |