The winning Delaware Play 4 numbers for July 12, 1999 were: day 7-7-7-3; night 2-9-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 12, 1999 | Night | 2-9-3-0 | 14 | 5 |
| Jul 12, 1999 | Day | 7-7-7-3 | 24 | 6 |
| Jul 11, 1999 | Night | 8-9-1-6 | 24 | 6 |
| Jul 10, 1999 | Night | 2-0-1-9 | 12 | 3 |
| Jul 10, 1999 | Day | 5-5-2-8 | 20 | 2 |
| Jul 9, 1999 | Night | 8-6-9-0 | 23 | 5 |
| Jul 9, 1999 | Day | 5-1-7-8 | 21 | 3 |
| Jul 8, 1999 | Night | 9-3-8-5 | 25 | 7 |
| Jul 8, 1999 | Day | 9-9-0-7 | 25 | 7 |
| Jul 7, 1999 | Night | 8-3-1-9 | 21 | 3 |
| Jul 7, 1999 | Day | 5-6-9-4 | 24 | 6 |
| Jul 6, 1999 | Night | 9-5-7-1 | 22 | 4 |
| Jul 6, 1999 | Day | 6-8-3-7 | 24 | 6 |