The winning Delaware Play 4 numbers for June 13, 1999 were: night 1-2-2-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jun 13, 1999 | Night | 1-2-2-2 | 7 | 7 |
| Jun 12, 1999 | Night | 9-8-7-8 | 32 | 5 |
| Jun 12, 1999 | Day | 9-1-2-1 | 13 | 4 |
| Jun 11, 1999 | Night | 6-2-3-9 | 20 | 2 |
| Jun 11, 1999 | Day | 1-3-8-9 | 21 | 3 |
| Jun 10, 1999 | Night | 9-4-2-4 | 19 | 1 |
| Jun 10, 1999 | Day | 4-3-5-8 | 20 | 2 |
| Jun 9, 1999 | Night | 5-6-7-7 | 25 | 7 |
| Jun 9, 1999 | Day | 0-4-7-3 | 14 | 5 |
| Jun 8, 1999 | Night | 5-8-4-9 | 26 | 8 |
| Jun 8, 1999 | Day | 6-4-8-6 | 24 | 6 |
| Jun 7, 1999 | Night | 3-9-6-3 | 21 | 3 |
| Jun 7, 1999 | Day | 5-8-8-3 | 24 | 6 |