The winning Delaware Play 4 numbers for December 9, 1998 were: day 3-0-3-1; night 5-2-6-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 1998 | Night | 5-2-6-3 | 16 | 7 |
| Dec 9, 1998 | Day | 3-0-3-1 | 7 | 7 |
| Dec 8, 1998 | Night | 2-4-8-1 | 15 | 6 |
| Dec 8, 1998 | Day | 5-8-7-8 | 28 | 1 |
| Dec 7, 1998 | Night | 4-7-7-2 | 20 | 2 |
| Dec 7, 1998 | Day | 6-9-8-2 | 25 | 7 |
| Dec 6, 1998 | Night | 7-4-9-6 | 26 | 8 |
| Dec 5, 1998 | Night | 8-9-1-1 | 19 | 1 |
| Dec 5, 1998 | Day | 3-6-7-9 | 25 | 7 |
| Dec 4, 1998 | Night | 6-3-4-3 | 16 | 7 |
| Dec 4, 1998 | Day | 1-9-8-0 | 18 | 9 |
| Dec 3, 1998 | Night | 9-5-2-7 | 23 | 5 |
| Dec 3, 1998 | Day | 5-8-0-3 | 16 | 7 |