The winning Delaware Play 4 numbers for December 22, 1996 were: night 6-3-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 22, 1996 | Night | 6-3-5-0 | 14 | 5 |
| Dec 21, 1996 | Night | 6-0-8-6 | 20 | 2 |
| Dec 21, 1996 | Day | 9-9-2-3 | 23 | 5 |
| Dec 20, 1996 | Night | 7-9-0-9 | 25 | 7 |
| Dec 20, 1996 | Day | 3-0-4-9 | 16 | 7 |
| Dec 19, 1996 | Night | 5-5-2-2 | 14 | 5 |
| Dec 19, 1996 | Day | 7-5-9-0 | 21 | 3 |
| Dec 18, 1996 | Night | 3-1-4-0 | 8 | 8 |
| Dec 18, 1996 | Day | 4-9-0-6 | 19 | 1 |
| Dec 17, 1996 | Night | 6-0-0-1 | 7 | 7 |
| Dec 17, 1996 | Day | 1-3-9-5 | 18 | 9 |
| Dec 16, 1996 | Night | 0-0-6-2 | 8 | 8 |
| Dec 16, 1996 | Day | 5-8-0-7 | 20 | 2 |