The winning Delaware Play 4 numbers for December 22, 1993 were: day 9-5-5-6; night 7-2-1-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 22, 1993 | Night | 7-2-1-8 | 18 | 9 |
| Dec 22, 1993 | Day | 9-5-5-6 | 25 | 7 |
| Dec 21, 1993 | Night | 1-0-8-5 | 14 | 5 |
| Dec 21, 1993 | Day | 3-6-4-8 | 21 | 3 |
| Dec 20, 1993 | Night | 7-8-8-7 | 30 | 3 |
| Dec 20, 1993 | Day | 0-8-3-7 | 18 | 9 |
| Dec 19, 1993 | Night | 8-6-3-2 | 19 | 1 |
| Dec 18, 1993 | Night | 7-8-3-1 | 19 | 1 |
| Dec 18, 1993 | Day | 6-5-9-7 | 27 | 9 |
| Dec 17, 1993 | Night | 6-7-6-5 | 24 | 6 |
| Dec 17, 1993 | Day | 5-8-0-0 | 13 | 4 |
| Dec 16, 1993 | Night | 3-3-4-0 | 10 | 1 |
| Dec 16, 1993 | Day | 1-0-9-8 | 18 | 9 |