The winning Delaware Play 4 numbers for December 8, 1993 were: day 5-6-6-4; night 9-3-9-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 8, 1993 | Night | 9-3-9-1 | 22 | 4 |
| Dec 8, 1993 | Day | 5-6-6-4 | 21 | 3 |
| Dec 7, 1993 | Night | 3-2-6-6 | 17 | 8 |
| Dec 7, 1993 | Day | 2-0-7-6 | 15 | 6 |
| Dec 6, 1993 | Night | 1-8-3-7 | 19 | 1 |
| Dec 6, 1993 | Day | 5-8-1-7 | 21 | 3 |
| Dec 5, 1993 | Night | 5-9-0-5 | 19 | 1 |
| Dec 4, 1993 | Night | 8-8-2-9 | 27 | 9 |
| Dec 4, 1993 | Day | 6-4-7-8 | 25 | 7 |
| Dec 3, 1993 | Night | 8-5-4-9 | 26 | 8 |
| Dec 3, 1993 | Day | 7-1-4-3 | 15 | 6 |
| Dec 2, 1993 | Night | 4-0-8-0 | 12 | 3 |
| Dec 2, 1993 | Day | 7-0-0-5 | 12 | 3 |