The winning Delaware Play 4 numbers for November 28, 1993 were: night 4-8-4-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 28, 1993 | Night | 4-8-4-6 | 22 | 4 |
| Nov 27, 1993 | Night | 8-7-1-9 | 25 | 7 |
| Nov 27, 1993 | Day | 1-2-1-8 | 12 | 3 |
| Nov 26, 1993 | Night | 9-1-7-9 | 26 | 8 |
| Nov 26, 1993 | Day | 4-6-4-9 | 23 | 5 |
| Nov 25, 1993 | Night | 9-9-2-8 | 28 | 1 |
| Nov 25, 1993 | Day | 7-4-3-6 | 20 | 2 |
| Nov 24, 1993 | Night | 2-2-2-5 | 11 | 2 |
| Nov 24, 1993 | Day | 3-7-8-5 | 23 | 5 |
| Nov 23, 1993 | Night | 6-1-5-0 | 12 | 3 |
| Nov 23, 1993 | Day | 8-8-7-2 | 25 | 7 |
| Nov 22, 1993 | Night | 4-4-1-8 | 17 | 8 |
| Nov 22, 1993 | Day | 5-8-6-4 | 23 | 5 |