The winning Delaware Play 4 numbers for November 7, 1993 were: night 6-5-2-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 7, 1993 | Night | 6-5-2-4 | 17 | 8 |
| Nov 6, 1993 | Night | 3-5-9-4 | 21 | 3 |
| Nov 6, 1993 | Day | 3-7-8-7 | 25 | 7 |
| Nov 5, 1993 | Night | 0-7-4-7 | 18 | 9 |
| Nov 5, 1993 | Day | 3-5-9-4 | 21 | 3 |
| Nov 4, 1993 | Night | 7-2-3-9 | 21 | 3 |
| Nov 4, 1993 | Day | 7-4-3-3 | 17 | 8 |
| Nov 3, 1993 | Night | 6-7-7-5 | 25 | 7 |
| Nov 3, 1993 | Day | 1-6-7-2 | 16 | 7 |
| Nov 2, 1993 | Night | 3-8-1-6 | 18 | 9 |
| Nov 2, 1993 | Day | 4-7-9-2 | 22 | 4 |
| Nov 1, 1993 | Night | 3-6-0-3 | 12 | 3 |
| Nov 1, 1993 | Day | 2-0-7-2 | 11 | 2 |