The winning Delaware Play 4 numbers for October 31, 1993 were: night 3-3-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 31, 1993 | Night | 3-3-7-0 | 13 | 4 |
| Oct 30, 1993 | Night | 7-4-4-5 | 20 | 2 |
| Oct 30, 1993 | Day | 5-8-5-5 | 23 | 5 |
| Oct 29, 1993 | Night | 2-7-3-0 | 12 | 3 |
| Oct 29, 1993 | Day | 7-4-4-5 | 20 | 2 |
| Oct 28, 1993 | Night | 6-3-6-4 | 19 | 1 |
| Oct 28, 1993 | Day | 6-6-1-0 | 13 | 4 |
| Oct 27, 1993 | Night | 2-2-9-5 | 18 | 9 |
| Oct 27, 1993 | Day | 4-1-2-0 | 7 | 7 |
| Oct 26, 1993 | Night | 6-8-5-3 | 22 | 4 |
| Oct 26, 1993 | Day | 4-0-2-1 | 7 | 7 |
| Oct 25, 1993 | Night | 0-7-7-7 | 21 | 3 |
| Oct 25, 1993 | Day | 3-3-6-0 | 12 | 3 |