The winning Delaware Play 4 numbers for September 17, 1993 were: day 0-6-4-0; night 9-0-5-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 17, 1993 | Night | 9-0-5-7 | 21 | 3 |
| Sep 17, 1993 | Day | 0-6-4-0 | 10 | 1 |
| Sep 16, 1993 | Night | 9-7-9-0 | 25 | 7 |
| Sep 16, 1993 | Day | 0-8-2-9 | 19 | 1 |
| Sep 15, 1993 | Night | 4-1-3-2 | 10 | 1 |
| Sep 15, 1993 | Day | 4-7-5-6 | 22 | 4 |
| Sep 14, 1993 | Night | 5-7-8-2 | 22 | 4 |
| Sep 14, 1993 | Day | 0-9-7-7 | 23 | 5 |
| Sep 13, 1993 | Night | 4-2-5-7 | 18 | 9 |
| Sep 13, 1993 | Day | 5-9-0-5 | 19 | 1 |
| Sep 12, 1993 | Night | 1-5-1-6 | 13 | 4 |
| Sep 11, 1993 | Night | 7-6-5-8 | 26 | 8 |
| Sep 11, 1993 | Day | 4-9-8-3 | 24 | 6 |