The winning Delaware Play 4 numbers for July 18, 1993 were: night 8-7-6-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 18, 1993 | Night | 8-7-6-9 | 30 | 3 |
| Jul 17, 1993 | Night | 0-5-4-4 | 13 | 4 |
| Jul 17, 1993 | Day | 5-1-8-9 | 23 | 5 |
| Jul 16, 1993 | Night | 2-5-7-2 | 16 | 7 |
| Jul 16, 1993 | Day | 5-9-2-1 | 17 | 8 |
| Jul 15, 1993 | Night | 9-7-7-4 | 27 | 9 |
| Jul 15, 1993 | Day | 1-9-4-1 | 15 | 6 |
| Jul 14, 1993 | Night | 4-5-5-4 | 18 | 9 |
| Jul 14, 1993 | Day | 7-6-0-0 | 13 | 4 |
| Jul 13, 1993 | Night | 5-2-9-4 | 20 | 2 |
| Jul 13, 1993 | Day | 6-4-1-9 | 20 | 2 |
| Jul 12, 1993 | Night | 5-7-3-5 | 20 | 2 |
| Jul 12, 1993 | Day | 1-7-4-3 | 15 | 6 |