The winning Delaware Play 4 numbers for December 9, 1990 were: night 4-4-6-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 1990 | Night | 4-4-6-5 | 19 | 1 |
| Dec 8, 1990 | Night | 7-3-5-8 | 23 | 5 |
| Dec 7, 1990 | Night | 3-5-6-1 | 15 | 6 |
| Dec 6, 1990 | Night | 1-0-4-9 | 14 | 5 |
| Dec 5, 1990 | Night | 0-5-8-8 | 21 | 3 |
| Dec 4, 1990 | Night | 8-5-8-7 | 28 | 1 |
| Dec 3, 1990 | Night | 1-5-2-4 | 12 | 3 |