The winning Delaware Play 4 numbers for November 8, 1990 were: night 1-8-1-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 8, 1990 | Night | 1-8-1-2 | 12 | 3 |
| Nov 7, 1990 | Night | 7-5-5-3 | 20 | 2 |
| Nov 6, 1990 | Night | 5-9-6-5 | 25 | 7 |
| Nov 5, 1990 | Night | 9-0-4-4 | 17 | 8 |
| Nov 4, 1990 | Night | 3-2-5-3 | 13 | 4 |
| Nov 3, 1990 | Night | 0-9-2-5 | 16 | 7 |
| Nov 2, 1990 | Night | 5-0-9-0 | 14 | 5 |