The winning Delaware Play 4 numbers for October 15, 1990 were: night 2-9-5-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 15, 1990 | Night | 2-9-5-2 | 18 | 9 |
| Oct 14, 1990 | Night | 1-2-0-7 | 10 | 1 |
| Oct 13, 1990 | Night | 8-6-4-1 | 19 | 1 |
| Oct 12, 1990 | Night | 0-8-0-3 | 11 | 2 |
| Oct 11, 1990 | Night | 6-2-0-9 | 17 | 8 |
| Oct 10, 1990 | Night | 2-6-1-2 | 11 | 2 |
| Oct 9, 1990 | Night | 0-3-0-4 | 7 | 7 |