The winning Delaware Play 4 numbers for August 7, 1990 were: night 3-1-2-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 7, 1990 | Night | 3-1-2-9 | 15 | 6 |
| Aug 6, 1990 | Night | 9-2-9-1 | 21 | 3 |
| Aug 4, 1990 | Night | 0-4-1-9 | 14 | 5 |
| Aug 3, 1990 | Night | 1-7-7-0 | 15 | 6 |
| Aug 2, 1990 | Night | 7-7-6-7 | 27 | 9 |
| Aug 1, 1990 | Night | 5-1-4-9 | 19 | 1 |