The winning Delaware Play 4 numbers for October 7, 1986 were: night 7-5-3-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 7, 1986 | Night | 7-5-3-4 | 19 | 1 |
| Oct 6, 1986 | Night | 1-1-3-0 | 5 | 5 |
| Oct 4, 1986 | Night | 6-3-6-8 | 23 | 5 |
| Oct 3, 1986 | Night | 2-4-5-1 | 12 | 3 |
| Oct 2, 1986 | Night | 6-9-2-1 | 18 | 9 |
| Oct 1, 1986 | Night | 4-9-2-9 | 24 | 6 |