The winning Delaware Play 4 numbers for October 19, 1983 were: night 5-9-7-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 19, 1983 | Night | 5-9-7-6 | 27 | 9 |
| Oct 17, 1983 | Night | 8-9-7-0 | 24 | 6 |
| Oct 14, 1983 | Night | 4-1-1-1 | 7 | 7 |