The winning Delaware Play 4 numbers for September 7, 1983 were: night 0-1-5-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 7, 1983 | Night | 0-1-5-7 | 13 | 4 |
| Sep 5, 1983 | Night | 8-2-6-1 | 17 | 8 |
| Sep 2, 1983 | Night | 5-4-9-3 | 21 | 3 |