The winning Delaware Play 4 numbers for July 1, 1983 were: night 5-2-3-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 1, 1983 | Night | 5-2-3-1 | 11 | 2 |
| Jun 29, 1983 | Night | 9-8-6-7 | 30 | 3 |
| Jun 27, 1983 | Night | 1-4-7-1 | 13 | 4 |