The winning Delaware Play 3 numbers for December 17, 2006 were: night 8-3-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 17, 2006 | Night | 8-3-1 | 12 | 3 |
| Dec 16, 2006 | Night | 5-3-2 | 10 | 1 |
| Dec 16, 2006 | Day | 2-9-4 | 15 | 6 |
| Dec 15, 2006 | Night | 1-0-3 | 4 | 4 |
| Dec 15, 2006 | Day | 6-5-5 | 16 | 7 |
| Dec 14, 2006 | Night | 4-4-8 | 16 | 7 |
| Dec 14, 2006 | Day | 6-8-3 | 17 | 8 |
| Dec 13, 2006 | Night | 1-3-0 | 4 | 4 |
| Dec 13, 2006 | Day | 2-5-7 | 14 | 5 |
| Dec 12, 2006 | Night | 2-1-4 | 7 | 7 |
| Dec 12, 2006 | Day | 9-5-9 | 23 | 5 |
| Dec 11, 2006 | Night | 3-5-6 | 14 | 5 |
| Dec 11, 2006 | Day | 8-2-0 | 10 | 1 |