The winning Delaware Play 3 numbers for December 3, 2006 were: night 7-9-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 3, 2006 | Night | 7-9-4 | 20 | 2 |
| Dec 2, 2006 | Night | 6-0-0 | 6 | 6 |
| Dec 2, 2006 | Day | 7-9-8 | 24 | 6 |
| Dec 1, 2006 | Night | 1-2-5 | 8 | 8 |
| Dec 1, 2006 | Day | 4-5-5 | 14 | 5 |
| Nov 30, 2006 | Night | 9-5-8 | 22 | 4 |
| Nov 30, 2006 | Day | 0-7-0 | 7 | 7 |
| Nov 29, 2006 | Night | 5-9-2 | 16 | 7 |
| Nov 29, 2006 | Day | 2-6-2 | 10 | 1 |
| Nov 28, 2006 | Night | 0-0-2 | 2 | 2 |
| Nov 28, 2006 | Day | 5-5-4 | 14 | 5 |
| Nov 27, 2006 | Night | 7-7-4 | 18 | 9 |
| Nov 27, 2006 | Day | 4-2-4 | 10 | 1 |