The winning Delaware Play 3 numbers for December 14, 2003 were: night 5-8-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 14, 2003 | Night | 5-8-1 | 14 | 5 |
| Dec 13, 2003 | Night | 9-1-8 | 18 | 9 |
| Dec 13, 2003 | Day | 3-9-3 | 15 | 6 |
| Dec 12, 2003 | Night | 0-1-8 | 9 | 9 |
| Dec 12, 2003 | Day | 7-7-6 | 20 | 2 |
| Dec 11, 2003 | Night | 5-8-0 | 13 | 4 |
| Dec 11, 2003 | Day | 5-9-6 | 20 | 2 |
| Dec 10, 2003 | Night | 2-4-9 | 15 | 6 |
| Dec 10, 2003 | Day | 1-5-3 | 9 | 9 |
| Dec 9, 2003 | Night | 0-7-3 | 10 | 1 |
| Dec 9, 2003 | Day | 2-2-7 | 11 | 2 |
| Dec 8, 2003 | Night | 5-2-6 | 13 | 4 |
| Dec 8, 2003 | Day | 4-5-6 | 15 | 6 |