The winning Delaware Play 3 numbers for November 16, 2003 were: night 0-3-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 16, 2003 | Night | 0-3-4 | 7 | 7 |
| Nov 15, 2003 | Night | 1-2-8 | 11 | 2 |
| Nov 15, 2003 | Day | 8-5-4 | 17 | 8 |
| Nov 14, 2003 | Night | 1-5-6 | 12 | 3 |
| Nov 14, 2003 | Day | 8-5-0 | 13 | 4 |
| Nov 13, 2003 | Night | 0-0-9 | 9 | 9 |
| Nov 13, 2003 | Day | 2-9-6 | 17 | 8 |
| Nov 12, 2003 | Night | 6-2-0 | 8 | 8 |
| Nov 12, 2003 | Day | 9-3-6 | 18 | 9 |
| Nov 11, 2003 | Night | 5-6-5 | 16 | 7 |
| Nov 11, 2003 | Day | 1-8-7 | 16 | 7 |
| Nov 10, 2003 | Night | 8-7-7 | 22 | 4 |
| Nov 10, 2003 | Day | 3-2-2 | 7 | 7 |