The winning Delaware Play 3 numbers for November 7, 2003 were: day 2-3-1; night 3-4-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 7, 2003 | Night | 3-4-7 | 14 | 5 |
| Nov 7, 2003 | Day | 2-3-1 | 6 | 6 |
| Nov 6, 2003 | Night | 8-8-3 | 19 | 1 |
| Nov 6, 2003 | Day | 2-8-6 | 16 | 7 |
| Nov 5, 2003 | Night | 5-0-0 | 5 | 5 |
| Nov 5, 2003 | Day | 5-5-0 | 10 | 1 |
| Nov 4, 2003 | Night | 4-6-9 | 19 | 1 |
| Nov 4, 2003 | Day | 9-4-0 | 13 | 4 |
| Nov 3, 2003 | Night | 2-9-1 | 12 | 3 |
| Nov 3, 2003 | Day | 8-1-7 | 16 | 7 |
| Nov 2, 2003 | Night | 6-3-5 | 14 | 5 |
| Nov 1, 2003 | Night | 7-7-3 | 17 | 8 |
| Nov 1, 2003 | Day | 7-7-7 | 21 | 3 |