The winning Delaware Play 3 numbers for September 9, 2003 were: day 9-6-9; night 1-1-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 9, 2003 | Night | 1-1-1 | 3 | 3 |
| Sep 9, 2003 | Day | 9-6-9 | 24 | 6 |
| Sep 8, 2003 | Night | 8-3-3 | 14 | 5 |
| Sep 8, 2003 | Day | 9-0-4 | 13 | 4 |
| Sep 7, 2003 | Night | 5-3-6 | 14 | 5 |
| Sep 6, 2003 | Night | 6-8-7 | 21 | 3 |
| Sep 6, 2003 | Day | 9-3-0 | 12 | 3 |
| Sep 5, 2003 | Night | 0-0-4 | 4 | 4 |
| Sep 5, 2003 | Day | 9-9-1 | 19 | 1 |
| Sep 4, 2003 | Night | 3-9-9 | 21 | 3 |
| Sep 4, 2003 | Day | 4-5-0 | 9 | 9 |
| Sep 3, 2003 | Night | 4-7-5 | 16 | 7 |
| Sep 3, 2003 | Day | 5-3-2 | 10 | 1 |