The winning Delaware Play 3 numbers for December 8, 2002 were: night 0-1-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 8, 2002 | Night | 0-1-4 | 5 | 5 |
| Dec 7, 2002 | Night | 3-9-7 | 19 | 1 |
| Dec 7, 2002 | Day | 8-2-7 | 17 | 8 |
| Dec 6, 2002 | Night | 7-7-7 | 21 | 3 |
| Dec 6, 2002 | Day | 5-7-0 | 12 | 3 |
| Dec 5, 2002 | Night | 0-0-1 | 1 | 1 |
| Dec 5, 2002 | Day | 7-2-7 | 16 | 7 |
| Dec 4, 2002 | Night | 5-1-5 | 11 | 2 |
| Dec 4, 2002 | Day | 8-1-9 | 18 | 9 |
| Dec 3, 2002 | Night | 5-1-8 | 14 | 5 |
| Dec 3, 2002 | Day | 7-0-6 | 13 | 4 |
| Dec 2, 2002 | Night | 5-9-7 | 21 | 3 |
| Dec 2, 2002 | Day | 7-0-2 | 9 | 9 |