The winning Delaware Play 3 numbers for December 9, 1999 were: day 9-4-1; night 6-1-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 1999 | Night | 6-1-3 | 10 | 1 |
| Dec 9, 1999 | Day | 9-4-1 | 14 | 5 |
| Dec 8, 1999 | Night | 8-8-7 | 23 | 5 |
| Dec 8, 1999 | Day | 9-5-8 | 22 | 4 |
| Dec 7, 1999 | Night | 7-9-2 | 18 | 9 |
| Dec 7, 1999 | Day | 9-9-8 | 26 | 8 |
| Dec 6, 1999 | Night | 6-5-0 | 11 | 2 |
| Dec 6, 1999 | Day | 1-6-0 | 7 | 7 |
| Dec 5, 1999 | Night | 6-5-7 | 18 | 9 |
| Dec 4, 1999 | Night | 3-7-2 | 12 | 3 |
| Dec 4, 1999 | Day | 1-0-0 | 1 | 1 |
| Dec 3, 1999 | Night | 8-1-3 | 12 | 3 |
| Dec 3, 1999 | Day | 7-0-2 | 9 | 9 |