The winning Delaware Play 3 numbers for December 2, 1999 were: day 2-2-4; night 6-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 1999 | Night | 6-7-5 | 18 | 9 |
| Dec 2, 1999 | Day | 2-2-4 | 8 | 8 |
| Dec 1, 1999 | Night | 6-1-7 | 14 | 5 |
| Dec 1, 1999 | Day | 6-1-0 | 7 | 7 |
| Nov 30, 1999 | Night | 8-9-4 | 21 | 3 |
| Nov 30, 1999 | Day | 6-7-3 | 16 | 7 |
| Nov 29, 1999 | Night | 2-6-1 | 9 | 9 |
| Nov 29, 1999 | Day | 0-0-5 | 5 | 5 |
| Nov 28, 1999 | Night | 5-6-5 | 16 | 7 |
| Nov 27, 1999 | Night | 7-7-0 | 14 | 5 |
| Nov 27, 1999 | Day | 6-7-1 | 14 | 5 |
| Nov 26, 1999 | Night | 6-3-7 | 16 | 7 |
| Nov 26, 1999 | Day | 5-1-3 | 9 | 9 |