The winning Delaware Play 3 numbers for November 10, 1999 were: day 2-2-2; night 2-6-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 10, 1999 | Night | 2-6-6 | 14 | 5 |
| Nov 10, 1999 | Day | 2-2-2 | 6 | 6 |
| Nov 9, 1999 | Night | 2-0-7 | 9 | 9 |
| Nov 9, 1999 | Day | 5-1-2 | 8 | 8 |
| Nov 8, 1999 | Night | 6-0-4 | 10 | 1 |
| Nov 8, 1999 | Day | 4-0-3 | 7 | 7 |
| Nov 7, 1999 | Night | 9-4-0 | 13 | 4 |
| Nov 6, 1999 | Night | 1-2-9 | 12 | 3 |
| Nov 6, 1999 | Day | 9-3-9 | 21 | 3 |
| Nov 5, 1999 | Night | 7-6-5 | 18 | 9 |
| Nov 5, 1999 | Day | 3-0-4 | 7 | 7 |
| Nov 4, 1999 | Night | 9-7-4 | 20 | 2 |
| Nov 4, 1999 | Day | 2-6-5 | 13 | 4 |