The winning Delaware Play 3 numbers for November 1, 1999 were: day 4-5-3; night 1-0-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 1, 1999 | Night | 1-0-4 | 5 | 5 |
| Nov 1, 1999 | Day | 4-5-3 | 12 | 3 |
| Oct 31, 1999 | Night | 0-0-8 | 8 | 8 |
| Oct 30, 1999 | Night | 3-0-8 | 11 | 2 |
| Oct 30, 1999 | Day | 3-6-3 | 12 | 3 |
| Oct 29, 1999 | Night | 3-4-9 | 16 | 7 |
| Oct 29, 1999 | Day | 9-4-9 | 22 | 4 |
| Oct 28, 1999 | Night | 8-0-7 | 15 | 6 |
| Oct 28, 1999 | Day | 8-6-9 | 23 | 5 |
| Oct 27, 1999 | Night | 4-2-7 | 13 | 4 |
| Oct 27, 1999 | Day | 5-2-2 | 9 | 9 |
| Oct 26, 1999 | Night | 3-0-4 | 7 | 7 |
| Oct 26, 1999 | Day | 5-3-5 | 13 | 4 |