The winning Delaware Play 3 numbers for October 12, 1999 were: day 6-5-0; night 6-8-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 12, 1999 | Night | 6-8-1 | 15 | 6 |
| Oct 12, 1999 | Day | 6-5-0 | 11 | 2 |
| Oct 11, 1999 | Night | 1-4-2 | 7 | 7 |
| Oct 11, 1999 | Day | 1-6-2 | 9 | 9 |
| Oct 10, 1999 | Night | 1-4-5 | 10 | 1 |
| Oct 9, 1999 | Night | 5-7-3 | 15 | 6 |
| Oct 9, 1999 | Day | 4-5-5 | 14 | 5 |
| Oct 8, 1999 | Night | 9-7-1 | 17 | 8 |
| Oct 8, 1999 | Day | 8-4-7 | 19 | 1 |
| Oct 7, 1999 | Night | 3-3-2 | 8 | 8 |
| Oct 7, 1999 | Day | 3-1-2 | 6 | 6 |
| Oct 6, 1999 | Night | 8-5-8 | 21 | 3 |
| Oct 6, 1999 | Day | 9-8-0 | 17 | 8 |