The winning Delaware Play 3 numbers for October 3, 1999 were: night 7-0-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 3, 1999 | Night | 7-0-1 | 8 | 8 |
| Oct 2, 1999 | Night | 7-1-9 | 17 | 8 |
| Oct 2, 1999 | Day | 2-7-7 | 16 | 7 |
| Oct 1, 1999 | Night | 8-4-1 | 13 | 4 |
| Oct 1, 1999 | Day | 4-5-8 | 17 | 8 |
| Sep 30, 1999 | Night | 5-6-0 | 11 | 2 |
| Sep 30, 1999 | Day | 3-7-0 | 10 | 1 |
| Sep 29, 1999 | Night | 5-9-9 | 23 | 5 |
| Sep 29, 1999 | Day | 5-9-0 | 14 | 5 |
| Sep 28, 1999 | Night | 2-0-9 | 11 | 2 |
| Sep 28, 1999 | Day | 4-6-9 | 19 | 1 |
| Sep 27, 1999 | Night | 5-0-8 | 13 | 4 |
| Sep 27, 1999 | Day | 8-0-3 | 11 | 2 |